Sound System
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Posts: n/a
Re: Sound System
Guy King wrote:
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
Guest
Posts: n/a
Re: Sound System
Guy King wrote:
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
Guest
Posts: n/a
Re: Sound System
Guy King wrote:
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
Guest
Posts: n/a
Re: Sound System
Guy King wrote:
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
> The message <11b129df8svro3b@news.supernews.com>
> from Mike Smith <mikeUNDERSCOREsmith@acm.org> contains these words:
>
>
>>Not true. Higher-impedance loads are easier to drive for a solid-state
>>amp, not harder.
>
>
> True, but of course as the impedance rises the voltage required to
> attain the same output also rises. Given you've only got a 12v supply
> available things can get a little tricky with 8R speakers.
Modern amps with switching power supplies can "chop" the signal at high
frequency and increase the available voltage. Only relatively low
powered amps use a 12V supply. Think about it; P = V^2/R. If V is 12V,
and R is 2Ohm, the most power you could ever get would be 72W, for 4Ohm
speakers only 36W. Obviously higher supply voltages are being used in
higher-power amps.
--
Mike Smith
Guest
Posts: n/a
Re: Sound System
The message <11bs8bbptt2llba@news.supernews.com>
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
Guest
Posts: n/a
Re: Sound System
The message <11bs8bbptt2llba@news.supernews.com>
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
Guest
Posts: n/a
Re: Sound System
The message <11bs8bbptt2llba@news.supernews.com>
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
Guest
Posts: n/a
Re: Sound System
The message <11bs8bbptt2llba@news.supernews.com>
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
from Mike Smith <mike_UNDERSCORE_smith@acm.DOT.org> contains these words:
> Obviously higher supply voltages are being used in
> higher-power amps.
Yes, I didn't think about it, having never had need for more than a few
watts myself. I've built step up voltage convertors before to charge
higher voltage batteries than a 12V feed will allow.
--
Skipweasel.
Ivor Cutler - "Never knowingly understood."
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Florin MIHUT
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