audi and kaipola ski jump advertisiement - climbing an icy hill
#101
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Erik-Jan Geniets" wrote
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
#102
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Erik-Jan Geniets" wrote
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
#103
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Erik-Jan Geniets" wrote
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
> Here they are: http://www.fotograaf.com/trooper/image.htm
Interesting picture.
I've never seen an clinometer of this kind,
but I can explain how it works:
Outer upper scale means up hill in percent (not grade),
outer lower scale down hill,
inner upper scale acceleration,
inner lower scale negative acc. (braking).
I.e. calculate what slope is equivalent to 3m/s^2:
3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
gradient (in percent) is the tangens =0.32.
The words "gut - schwach - schlecht" (good-week-bad)
are for indicating braking performance (on flat terrain).
But of course not applicable for modern cars
Cheers,
Thomas
#104
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Thomas Schäfer" wrote:
>
> "Erik-Jan Geniets" wrote
>
> > Here they are: http://www.fotograaf.com/trooper/image.htm
>
> Interesting picture.
> I've never seen an clinometer of this kind,
> but I can explain how it works:
> Outer upper scale means up hill in percent (not grade),
> outer lower scale down hill,
> inner upper scale acceleration,
> inner lower scale negative acc. (braking).
Yes, thanks. The questions on that old page are as old. 2002 I Guess.
In the mean time I figured out how it works.
The up and downhill percentages are very accurate compared to roadsigns
as long as you do not accelerate or brake.
Kind regards,
Erik-Jan.
> I.e. calculate what slope is equivalent to 3m/s^2:
> 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> gradient (in percent) is the tangens =0.32.
>
> The words "gut - schwach - schlecht" (good-week-bad)
> are for indicating braking performance (on flat terrain).
> But of course not applicable for modern cars
#105
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Thomas Schäfer" wrote:
>
> "Erik-Jan Geniets" wrote
>
> > Here they are: http://www.fotograaf.com/trooper/image.htm
>
> Interesting picture.
> I've never seen an clinometer of this kind,
> but I can explain how it works:
> Outer upper scale means up hill in percent (not grade),
> outer lower scale down hill,
> inner upper scale acceleration,
> inner lower scale negative acc. (braking).
Yes, thanks. The questions on that old page are as old. 2002 I Guess.
In the mean time I figured out how it works.
The up and downhill percentages are very accurate compared to roadsigns
as long as you do not accelerate or brake.
Kind regards,
Erik-Jan.
> I.e. calculate what slope is equivalent to 3m/s^2:
> 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> gradient (in percent) is the tangens =0.32.
>
> The words "gut - schwach - schlecht" (good-week-bad)
> are for indicating braking performance (on flat terrain).
> But of course not applicable for modern cars
#106
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
"Thomas Schäfer" wrote:
>
> "Erik-Jan Geniets" wrote
>
> > Here they are: http://www.fotograaf.com/trooper/image.htm
>
> Interesting picture.
> I've never seen an clinometer of this kind,
> but I can explain how it works:
> Outer upper scale means up hill in percent (not grade),
> outer lower scale down hill,
> inner upper scale acceleration,
> inner lower scale negative acc. (braking).
Yes, thanks. The questions on that old page are as old. 2002 I Guess.
In the mean time I figured out how it works.
The up and downhill percentages are very accurate compared to roadsigns
as long as you do not accelerate or brake.
Kind regards,
Erik-Jan.
> I.e. calculate what slope is equivalent to 3m/s^2:
> 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> gradient (in percent) is the tangens =0.32.
>
> The words "gut - schwach - schlecht" (good-week-bad)
> are for indicating braking performance (on flat terrain).
> But of course not applicable for modern cars
#107
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
In article <43CF9FCB.8A97B160@fotograaf.com>,
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
#108
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
In article <43CF9FCB.8A97B160@fotograaf.com>,
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
#109
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
In article <43CF9FCB.8A97B160@fotograaf.com>,
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
Erik-Jan Geniets <ej@fotograaf.com> wrote:
> "Thomas Schäfer" wrote:
> >
> > "Erik-Jan Geniets" wrote
> >
> > > Here they are: http://www.fotograaf.com/trooper/image.htm
> >
> > Interesting picture.
> > I've never seen an clinometer of this kind,
> > but I can explain how it works:
> > Outer upper scale means up hill in percent (not grade),
> > outer lower scale down hill,
> > inner upper scale acceleration,
> > inner lower scale negative acc. (braking).
>
> Yes, thanks. The questions on that old page are as old. 2002 I Guess.
> In the mean time I figured out how it works.
> The up and downhill percentages are very accurate compared to roadsigns
> as long as you do not accelerate or brake.
> Kind regards,
> Erik-Jan.
So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
>
>
> > I.e. calculate what slope is equivalent to 3m/s^2:
> > 3/9.8 (1g=9.8m/s^2) = 0.306 (the sinus of the angle)
> > gradient (in percent) is the tangens =0.32.
> >
> > The words "gut - schwach - schlecht" (good-week-bad)
> > are for indicating braking performance (on flat terrain).
> > But of course not applicable for modern cars
--
Alan Baker
Vancouver, British Columbia
"If you raise the ceiling 4 feet, move the fireplace from that wall
to that wall, you'll still only get the full stereophonic effect
if you sit in the bottom of that cupboard."
#110
Guest
Posts: n/a
Re: audi and kaipola ski jump advertisiement - climbing an icy hill
Alan Baker wrote:
>
> So I'm betting you were climbing a hill with a 20 - 30 *percent* grade...
Yes, also. Turacher Höhe in Austria, old Vulcano in Kärnten. Tarmac in
the winter. Some snow/ice here and there. 23 percent. At the base off
the mountain there is a road sign in German which reads "4 wheel drive
car's only"
Kind regards,
Erik-Jan.